// NOTE: it is recommended to use this even if you don't understand the following code.

#include <fstream>
#include <iostream>
#include <string>
#include <vector>
#define VMAX 50000

using namespace std;

bool dp[500][VMAX + 2];
int S = 0;

int main() {
    // uncomment the two following lines if you want to read/write from files
    // ifstream cin("input.txt");
    // ofstream cout("output.txt");

    ios::sync_with_stdio(false);
    cin.tie(nullptr);

    int N;
    cin >> N;

    vector<int> A(N);
    for (int i = 0; i < N; ++i){
        cin >> A[i]; S = S + A[i];
    }

    string ans = "";

    if(N == 1) cout << "-1";
    else if(N == 2){
         if(A[0] == A[1]){
            for(int i = 0; i < A[0]; i++) ans = ans + '(';
            for(int i = 0; i < A[0]; i++) ans = ans + ')';
        }
        else ans = "-1";
        cout << ans;
    }
    else{
        ///dp[i] = 1, ha nyitva van i zarojel
        ///A[i] - lehet nyito zarojel ==> hozzaadjuk az olyan zarojel sorozathoz ahol dp[j] = 1
        ///A[i] - lehet csuko zarojel ==> kivonjuk dp[j]=1-bol
        dp[0][A[0]] = 1;///az elso zarojel csak nyito lehet
        int M = A[0];
        for(int i = 1; i < N; i++){
            for(int j = M; j >= 0; j--){
                if(dp[i - 1][j] == 1){
                    dp[i][j + A[i]] = 1; M = max(M, j + A[i]);
                    if(j - A[i] >= 0) dp[i][j - A[i]] = 1;
                }
            }
        }
        if(dp[N - 1][0] == 0) cout << "-1";
        else{
            int k = 0;
            for(int i = N - 1; i > 0; i--){
                if(dp[i - 1][k + A[i]] == 1){
                    ///A[i] csuko
                    for(int j = 0; j < A[i]; j++) ans = ans + ')';
                    k = k + A[i];
                }
                else if(k >= A[i] and dp[i - 1][k - A[i]] == 1){
                    for(int j = 0; j < A[i]; j++) ans = ans + '(';
                    k = k - A[i];
                }
            }
            for(int i = 0; i < A[0]; i++) ans = ans + '(';
            for(int i = S - 1; i>= 0; --i) cout << ans[i];
        }
    }

    return 0;
}